argument by reference?

Can I pass any argument by reference?

function modify(reference_of($val))
{
$val="house";
}

$val = "my ";
echo($val);
modify($val);
echo($val);

Output:
my house

--
-Gernot
int main(int argc, char** argv) {printf
("%silto%c%cf%cgl%ssic%ccom%c", "ma", 58, 'g', 64, "ba", 46, 10);}

________________________________________
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Gernot Frisch wrote:
 > Can I pass any argument by reference?
 >

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JW